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34 lines
1.1 KiB
SQL
34 lines
1.1 KiB
SQL
-- name: GetLatestVersion :one
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WITH RECURSIVE search_tree(id, chain_id, chain_counter) AS (
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SELECT base.id, base.id AS chain_id, 0 as chain_counter
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FROM versions AS base
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WHERE base.previous_version_id IS NULL
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UNION ALL
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SELECT v.id, search_tree.chain_id, search_tree.chain_counter + 1
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FROM versions AS v
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INNER JOIN search_tree ON search_tree.id = v.previous_version_id
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)
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SELECT DISTINCT ON (search_tree.chain_id)
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search_tree.id
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FROM search_tree
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ORDER BY search_tree.chain_id, chain_counter DESC;
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-- name: GetLatestVersionWithSubquery :one
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SELECT id
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FROM versions
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WHERE versions.id IN (
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WITH RECURSIVE search_tree(id, chain_id, chain_counter) AS (
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SELECT base.id, base.id AS chain_id, 0 as chain_counter
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FROM versions AS base
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WHERE versions.previous_version_id IS NULL
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UNION ALL
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SELECT v.id, search_tree.chain_id, search_tree.chain_counter + 1
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FROM versions AS v
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INNER JOIN search_tree ON search_tree.id = v.previous_version_id
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)
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SELECT DISTINCT ON (search_tree.chain_id)
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search_tree.id
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FROM search_tree
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ORDER BY search_tree.chain_id, chain_counter DESC
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);
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